Preparation of Alcohols

Match the conversions with the reagents that are used in the process:

In the following sequence of reactions,

The compound D is –

When $1:2$ equivalence ratio of the gases $\mathrm{X}$ and $\mathrm{Y}$ are heated to $573\mathrm{K}-673 \mathrm{K}$ at $200 -300$ atm in the presence of $\mathrm{ZnO}-{\mathrm{Cr}}_2{\mathrm{O}}_3$ catalyst, methanol is formed. Here, the gases $\mathrm{X}$and $\mathrm{Y}$ are _____ and _____ respectively.

Which of the following compound gives $3$-Ethylpentan-$3$-ol by the action of ethyl magnesium iodide followed by acid hydrolysis?

Which of the following alcohols cannot be prepared by reduction of carbonyl compounds?

$\mathrm{R}-\mathrm{MgX}+\mathrm{HCHO} \to \left[\mathrm{P}\right],$here $\left[\mathrm{P}\right]$ is

Ethylene reacts with Baeyer's reagent to give

Which of the following will produce only one product on reduction with $\mathrm{L}\mathrm{i}\mathrm{A}\mathrm{l}{\mathrm{H}}_4?$

In the following reaction sequence: 

Compound $\mathrm{I}$ is

The gas evolved on heating $\mathrm{C}{\mathrm{H}}_3\mathrm{M}\mathrm{g}\mathrm{B}\mathrm{r}$ in methanol is:

Bouveault-Blanc reduction reaction involves:

In the hydroboration - oxidation reaction of propene with diborane, ${\mathrm{H}}_{\mathrm{2}}{\mathrm{O}}_{\mathrm{2}}$ and $\mathrm{NaOH},$ the organic compound formed is:

Which one of the following reactions would produce a secondary alcohol?

The reaction of ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CH}=\mathrm{CHCHO}$ with ${\mathrm{LiAlH}}_4$ gives

Which of the following can reduce ester to alcohol

Propene on oxidation with diborane in presence of alkaline hydrogen peroxide gives _______.

The major products $\mathrm{P}, \mathrm{Q}$ and $\mathrm{R}$ in the following reaction sequence, are

How many of the following compound will give alcohol as a product on treating with ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{MgBr}$

 $\left(\mathrm{i}\right) {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$

 $\left(\mathrm{ii}\right) {\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2$

$\left(\mathrm{iii}\right) {\mathrm{CH}}_3-\mathrm{CHO}$

 $\left(\mathrm{iv}\right) {\mathrm{CH}}_3{\mathrm{COCH}}_3$

$\left(\mathrm{v}\right)$

 $\left(\mathrm{vi}\right) {\mathrm{CH}}_3\mathrm{C}\equiv \mathrm{CH}$

 Product $\left(\mathrm{C}\right)$ is :